2(x^2-9)/x^2-4

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Solution for 2(x^2-9)/x^2-4 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*(x^2-9))/(x^2)-4 = 0

(2*(x^2-9))/(x^2)+(-4*x^2)/(x^2) = 0

2*(x^2-9)-4*x^2 = 0

-2*x^2-18 = 0

(-2*x^2-18)/(x^2) = 0

(-2*x^2-18)/(x^2) = 0 // * x^2

-2*x^2-18 = 0

-2*x^2 = 18 // : -2

x^2 = -9

x belongs to the empty set

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